Romer to Newton Converter
Convert Romer (°Rø) to Newton (°N)
Temperature Converter
v0.1.7-4.0857°N
1 Romer = -4.0857142857 Newton
Conversion Formula
7.5 °Rø = 0 °N
0 °N = 7.5 °Rø
How to Convert Romer to Newton
To convert Romer to Newton, use the formula: °N = (°Rø − 7.5) × 22/35
Newton = Romer × 1
Examples: 7.5 °Rø = 0 °N (freezing point), 60 °Rø = 33 °N (boiling point)
Romer to Newton Conversion Table
| Romer (°Rø) | Newton (°N) |
|---|---|
| -40 °Rø | -29.8571 °N |
| -20 °Rø | -17.2857 °N |
| -10 °Rø | -11 °N |
| 0 °Rø | -4.7143 °N |
| 10 °Rø | 1.5714 °N |
| 20 °Rø | 7.8571 °N |
| 25 °Rø | 11 °N |
| 30 °Rø | 14.1429 °N |
| 37 °Rø | 18.5429 °N |
| 40 °Rø | 20.4286 °N |
| 50 °Rø | 26.7143 °N |
| 100 °Rø | 58.1429 °N |
| 200 °Rø | 121 °N |
| 500 °Rø | 309.5714 °N |
| 1000 °Rø | 623.8571 °N |
About These Scales
°RøRomer
The Romer scale was proposed by Ole Christensen Romer in 1701. On this scale, water freezes at 7.5Ro and boils at 60Ro. It was used as a basis for the Fahrenheit scale.
°NNewton
The Newton scale was devised by Isaac Newton around 1700. On this scale, water freezes at 0N and boils at 33N. It was one of the first attempts to create a standardized temperature scale.